custom shader

# 1 08-11-2003 , 04:54 PM

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I was messing with shaders earlier. I connected the facing ratio attribute of a samplerInfo node to the reflectivity of a blinn shader. Now I want to invert the reflectivity i.e. when the facing ratio is 1 I want reflectivity to be 0 and viceversa.

I know I probably have to use the graph editor for this. But I'm not sure how to do it.

Can you please help me out?

Thanks.

~nspiratn

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# 2 08-11-2003 , 05:57 PM

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Have you tried experimetning with throwing a reverse and condition node into the mix?

"Terminat Bora Diem, Terminal Auctor opus."

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# 3 08-11-2003 , 08:07 PM

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Umm nope.

But Instead of adding more nodes in the network, wouldnt it just be easier to do it the way I mentioned in my previous post?

I saw a gnomon workshop video once where the guy did what I'm trying to do, I just don't have access to that video anymore so I can refer to it. So I've been wondering if anyone here knows how to do it.

~nspiratn

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# 4 08-11-2003 , 08:22 PM

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NitroLiq, I don't think I can connect the output of either the reverse node or the condition node to the reflectivity attribute of my shader because its a single value attribute as opposed to the outputs of reverse and condition which are triple value.

Right?

~nspiratn

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# 5 08-11-2003 , 08:22 PM

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There's lots of ways to do anything. Don't dismiss one person's way just because you've seen it done another. user added image

It might work better!

-Mike
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# 6 08-11-2003 , 08:23 PM

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Hehe I didnt dismiss it. user added image

Read my post above.

user added image

~nspiratn

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# 7 08-11-2003 , 08:24 PM

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ah, posted at same time. user added image

I'll keep my comment around for future use. lol

-Mike
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# 8 08-11-2003 , 08:26 PM

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Hehe.

But you were totally right, there user added image

Point taken.

~nspiratn

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# 9 09-11-2003 , 03:58 PM

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After doing a little reading, I'm not entirely sure a condition node would work anyway as I believe it's directly related to outcolor. Ive used it to create a double-sided shader before and was thinking along the lines that you could use it to make a condition that if facing ratio is 1, make the blinn's reflectivity 0 and if not, reverse it with the reverse node. What gnomon video were you originally referring to? If I have it, I might be able to look it up for you.

"Terminat Bora Diem, Terminal Auctor opus."

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# 10 09-11-2003 , 06:28 PM

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Oh. I'm pretty sure it was one of the polygon modeling videos where he builds a car.

He puts a reddish shader on the car. Thats when he does the thing witht he graph editor I think.

Thanks.

~nspiratn

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# 11 09-11-2003 , 09:07 PM

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Hmmm....I have the first two polygon modeling dvds and they're all modeling, no shading whatsoever (including the car). It wouldn't happen to be one of their video lectures on surface normals affecting reflectivity, would it?

"Terminat Bora Diem, Terminal Auctor opus."

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# 12 09-11-2003 , 09:20 PM

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Hmm Dunno. maybe its the nurbs modeling one then. Because I remember now that he starts with a sphere and then uses patches and detaches surfaces.

Its a cool looking futuristic car that he builds too.

~nspiratn

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# 13 10-11-2003 , 04:36 AM

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Not sure, Nir. I have the nurbs race car video as well and it doesn't really go into texturing. The only shader they have on the car is a metallic blue layered shader comprised of a blinn and anisotropic for reflective, clearcoat gloss. Wish I could help you further with this but I'm at a loss. Maybe if you explain, exactly what type of end result you're looking for (i.e how you want the shader to interact with light), someone can help you with an alternative way.

"Terminat Bora Diem, Terminal Auctor opus."

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# 14 10-11-2003 , 04:58 AM

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Oh, yeah, didn't think of that. What is most likely going on is a layered shader as Nitro mentions. The top layer is a reflective blinn or whatever with a sampler info connected to a blend color node (facing ratio > blender) which is then connected to the blinn's transparancy. The layer beneath could be the same blinn but with reflectivity turned off. If you make the two colors in the blend color black and white, you'll have the reflective material transparant in the center and opaque on the edges, thus giving you refletivity only on the outer edges.

Duh! Should've thought of that earlier. user added image

-Mike
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